Today is about my favorite probability puzzle – The Monty Hall problem. If you haven’t heard of it before you are in for a treat. The problem stated goes as follows (from Wikipedia):

*Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats*. You pick a door, say No. 1 [but the door is not opened], and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat**. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?*

**Vos Savant's response was that the contestant should always switch to the other door.**[…]*Many readers refused to believe that switching is beneficial. After the Monty Hall problem appeared in Parade, approximately 10,000 readers, including nearly 1,000 with PhDs, wrote to the magazine claiming that vos Savant was wrong. (*

*Tierney 1991*

*) Even when given explanations, simulations, and formal mathematical proofs, many people still do not accept that switching is the best strategy.*

*The probability of the car being behind any door is uniformly 1/3

**The door that is opened has to have a goat behind it, and it cannot be the one you picked initially, in case the host has multiple choices it is assumed that s/he chooses uniformly at random

The problem is brilliant in its simplicity and the correct answer feels extremely counter-intuitive at first. The natural tendency is to think that it makes no difference whether you switch or not – but the truth is that you

*should*switch! And hopefully once you are done reading this article you will be convinced why.